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3y^2-11y+3=0
a = 3; b = -11; c = +3;
Δ = b2-4ac
Δ = -112-4·3·3
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{85}}{2*3}=\frac{11-\sqrt{85}}{6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{85}}{2*3}=\frac{11+\sqrt{85}}{6} $
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